Sunday, October 18, 2015

২০১৩ সালের ৪র্থ বর্ষ নির্বাচনী পরীক্ষার প্রশ্নপত্র

miKvix Gg Gg K‡jR, h‡kvi| 4_© el© m¤§vb wbe©Pbx cix¶v-2013 ‡Kv‡m©i bvg t Partial Differential Equation ‡KvW: 3785 mgq : 4 N›Uv K - wefvM 1| ‡h †Kvb 10 wU cÖ‡kœi DËi `vI 10 1 = 10 (K) AvswkK AšÍiK mgxKiY Kv‡K e‡j| (L) AvswkK AšÍiK mgxKi‡Yi µg I NvZ ewj‡Z wK eyS ? (M) Gi AšÍiK mgxKiY MVb Ki| (N) Gi mgvav‡bi Rb¨ mnvqK mgxKiYwU wjL| (O) PviwcVm c×wZi wU wjL| (P) mgxKiYwUi mnvqK mgxKiYwU wjL| (Q) Gi we‡kl Bw›UMÖvjwU wjL| (R) GKwU `yB µ‡gi AvwksK AšÍiK mgxKiY wjL| (S) ei‡Z wK eyS ? (T) j¨vcjvm iƒcvšÍ‡ii msÁv wjL| (U) AvswkK AšÍiK mgxKiYwUi µg I NvZ wjL| (V) GKwU A‰iwLK AvswkK AšÍiK mgxKiY wjL| L- wefvM 2| ‡h †Kvb 4 wU cÖ‡kœi DËi `vI 4 5 = 20 (K) mgxKiY n‡Z AvswkK AšÍiK mgxKiY MVb Ki| (L) AvswkK AšÍiK mgxKiY mgvavb Ki| (M) AvswkK AšÍiK mgxKiY mgvavb Ki| (N) mgvavb Ki: (O) mgvavb Ki: (P) mgxKiY n‡Z AvswkK AšÍiK mgxKiY MVb Ki| (Q) n‡Z AvswkK AšÍiK mgxKiY MVb Ki| M- wefvM †h †Kvb 5 wU c‡kœi DËi `vI| 5 10=50 (K) j¨vMi¨v‡Äi ˆiwLK AšÍiK mgxKiYwU mgvavb Kivi c×wZ Av‡jvPbv Ki| (L) e„ËMvgx Zj †Mv·K j¤^fv‡e †Q` K‡I Ggb Z‡ji mgxKiY wbY©q Ki| (M) Pviwc‡Vi c×wZ cÖ‡qvM K‡i AšÍiK mgxKiYwUi GKwU c~Y©v½ Bw›UMÖvj wbY©q Ki| (N) cÖgvY Ki †h, Ges kZ© mv‡c‡¶ AšÍiK mgxKiYwUi mgvavb nj (PjK c„_KxKiY c×wZ‡Z) (O) Using the Fourier Transformation to solve (P) Reduce the equation to Canonical form. (Q) Applying Lap lace transformation Solve subject to the condition --0--

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